How much
potential energy will a linear spring have if it has a constant of
530 N/m and a displacement stretch of 0.24 m?
spring constant: k = 530 N/m
displacement: x = 0.24 m
Starting formula |
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Plug in numbers with units |
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Multiply: (1/2)(530)(0.24^2) = 15.264 |
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Final result with significant figures and unit |