An object with a mass of 2 kg is traveling along with a velocity of 3 m/s when a 5 N net force acts upon it. What will become the object's velocity if the force acts for 7 s?
Solution:
vf = vi + at
vf = vi + (F/m)t
vf = (3 m/s) + (5 N / 2 kg)(7 s)
vf = (3 m/s) + (2.5 m/s2)(7 s)
vf = (3 m/s) + (17.5 m/s)
vf = 20.5 m/s
Note:
a = F/m
a = (5 N) / (2 kg)
a = 2.5 m/s2
vi = 3 m/s F = 5 N m = 2 kg t = 7 s