An object with a mass of 2 kg is traveling along with a velocity of 3 m/s when a 5 N net force acts upon it. What will become the object's velocity if the force acts for 7 s?

Solution:

vf = vi + at

vf = vi + (F/m)t

vf = (3 m/s) + (5 N / 2 kg)(7 s)

vf = (3 m/s) + (2.5 m/s2)(7 s)

vf = (3 m/s) + (17.5 m/s)

vf = 20.5 m/s

Note:

a = F/m

a = (5 N) / (2 kg)

a = 2.5 m/s2

vi = 3 m/s F = 5 N m = 2 kg t = 7 s