# [2] XVA Demonstration, Constant Acceleration

xo =
vo =
a =
-100 100 -10 10 -2 2 10 10 10
x vs. t
v vs. t
a vs. t
x = 0
v = 0
a = 0
t = 0

[2] XVA - Constant Acceleration

xo = 0.0 m

vo = 0.0 m/s

a = 0.5 m/s2 (Try changing this to experiment.)

• The position of the object starts at 0.0 m.
• The velocity of the object starts at 0.0 m/s.
• The constant positive acceleration means that the velocity is added to. This causes the velocity to become more and more positive as time passes.
• The object speeds up in a positive direction.
• Since the value of the velocity is always positive, (except at vo = 0.0 m/s), and becomes increasingly more positive as time passes, the slope of the x vs. t graph is positive and becomes increasingly more positive as time passes. This is because the slope of the x vs. t graph is the velocity.
• Note that the x vs. t graph is curved since its slope is ever increasing as the velocity ever increases.
• Since the value of the acceleration is constant and positive, the slope of the v vs. t graph is constant and positive. This is because the slope of the v vs. t graph is the acceleration.

You can change this program's original parameters using the drop down lists near its top. This may aid your understanding. You can always go back to the original parameters using the values above or by reloading this page.

You can get help on running this program here.

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