XVA  Constant Position
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Here we are looking at the simplest type of
motion, that of an object which is standing still. Perhaps
many people would not even consider this a type of motion, but it is
a starting point from which to understand more complicated motions.
[1]
Here is the first of our constant position examples. The
object is resting at the origin of its position number line,
and time is passing. It is standing still at x = 0.0 m.
Back
x_{o}
= 0.0 m 
v_{o}
= 0.0 m/s^{ } 
a =
0.0 m/s^{2 } 



The object's position
starts at 0.0 m, and it stays at that
location as time passes. 
The object's velocity
starts at 0.0 m/s. It's velocity remains
at that value as time passes. 
The constant acceleration
is 0.0 m/s^{2}; so, the velocity
does not change as time passes. 

[1] XVA
demonstration 
Comments:
 The object is standing still.
 In all three of the above graphs the graph
line of the function is drawn directly over the time axis. So, it may at
first be difficult to see that there is actually data shown on
these graphs.
[2]
The object here is also standing still. Unlike the object in [1]
above, this object is not located at the origin. It
starts out 40.0 meters away from the origin in the positive
direction. It stays there.
Back
x_{o}
= 40.0 m 
v_{o}
= 0.0 m/s^{ } 
a =
0.0 m/s^{2 } 



The object's position
starts at 40.0 m, and it stays at that
location as time passes. 
The object's velocity
starts at 0.0 m/s. It's velocity remains
at that value as time passes. 
The constant acceleration
is 0.0 m/s^{2}; so, the velocity
does not change as time passes. 

[2] XVA
demonstration 
Comments:
 The object is standing still at a
place 40.0 m from the origin.
[3] Here, again, the object is motionless.
It is located
at positive 80.0 meters from the origin.
Back
x_{o}
= 80.0 m 
v_{o}
= 0.0 m/s^{ } 
a =
0.0 m/s^{2 } 



The object's position
starts at 80.0 m, and it stays at that
location as time passes. 
The object's velocity
starts at 0.0 m/s. It's velocity remains
at that value as time passes. 
The constant acceleration
is 0.0 m/s^{2}; so, the velocity
does not change as time passes. 

[3] XVA
demonstration 
Comments:
 Again, the object standing still at
another place. Now it's standing at x = 80. This is much like the object that is
standing still in example [2].
[4]
Be sure you understand what we mean by negative positions.
Here, the object is remaining motionless and located at x = 40.0
meters. It is on the other side of the origin than
the side it was on in the above three examples.
Back
x_{o}
= 40.0 m 
v_{o}
= 0.0 m/s^{ } 
a =
0.0 m/s^{2 } 



The object's position
starts at 40.0 m, and it stays at that
location as time passes. 
The object's velocity
starts at 0.0 m/s. It's velocity remains
at that value as time passes. 
The constant acceleration
is 0.0 m/s^{2}; so, the velocity
does not change as time passes. 

[4] XVA
demonstration 
Comments:
 The object is motionless located at a
position coordinate of 40 m.
 Note that the object's original
position can be at a negative or a positive coordinate.
 Usually, problems are set up considering
the object to be starting at the origin. But that is not always the case, nor
is it always desirable to set up a problem that way. So, be sure to
understand what is meant by having
the object start at a positive or negative
position.
[5] This is another example of an object
standing still at a negative position. Here, the object is
remaining motionless and located at 80.0 meters.
Back
x_{o}
= 80.0 m 
v_{o}
= 0.0 m/s^{ } 
a =
0.0 m/s^{2 } 



The object's position
starts at 80.0 m, and it stays at that
location as time ticks on. 
The object's velocity
starts at 0.0 m/s. It's velocity remains
at that value as time ticks on. 
The constant acceleration
is 0.0 m/s^{2}; so, the velocity
does not change as time ticks on. 

[5] XVA
demonstration 
Comments:
 Another object standing still at
another negative coordinate position. This is much
like the object that is standing still in example [4].
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